2^3-15x^2+22x-15=0

Solution for 2^3-15x^2+22x-15=0 equation:

2^3-15x^2+22x-15=0

We add all the numbers together, and all the variables

-15x^2+22x-7=0

a = -15; b = 22; c = -7;
Δ = b2-4ac
Δ = 222-4·(-15)·(-7)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-8}{2*-15}=\frac{-30}{-30}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+8}{2*-15}=\frac{-14}{-30}
=7/15
$